Final test: Bash: text processing and scripts

Question 2 of 18

Read the output

The log has lines with timeout and with refused. Why did grep print nothing?

$ grep 'timeout|refused' app.log
$ echo $?
1

The words in the log are written in capitals.
Without -E, | is an ordinary character to grep, so it searched for the text timeout|refused as a whole.
grep cannot search for two words in one command.
grep took the quoted pattern for a file name.

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